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x in (-oo:+oo)
6*(12-((2*x)/5)) = 0
6*((-2/5)*x+12) = 0
6*(12-2/5*x) = 0
( 12-2/5*x )
12-2/5*x = 0 // - 12
-2/5*x = -12 // : -2/5
x = -12/(-2/5)
x = 30
( 6 )
6 = 0
x belongs to the empty set
x = 30
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