3(4+3c)=4(c-2)

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Solution for 3(4+3c)=4(c-2) equation:


Simplifying
3(4 + 3c) = 4(c + -2)
(4 * 3 + 3c * 3) = 4(c + -2)
(12 + 9c) = 4(c + -2)

Reorder the terms:
12 + 9c = 4(-2 + c)
12 + 9c = (-2 * 4 + c * 4)
12 + 9c = (-8 + 4c)

Solving
12 + 9c = -8 + 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
12 + 9c + -4c = -8 + 4c + -4c

Combine like terms: 9c + -4c = 5c
12 + 5c = -8 + 4c + -4c

Combine like terms: 4c + -4c = 0
12 + 5c = -8 + 0
12 + 5c = -8

Add '-12' to each side of the equation.
12 + -12 + 5c = -8 + -12

Combine like terms: 12 + -12 = 0
0 + 5c = -8 + -12
5c = -8 + -12

Combine like terms: -8 + -12 = -20
5c = -20

Divide each side by '5'.
c = -4

Simplifying
c = -4

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