3(b-3)=-2(b+2)+20

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Solution for 3(b-3)=-2(b+2)+20 equation:


Simplifying
3(b + -3) = -2(b + 2) + 20

Reorder the terms:
3(-3 + b) = -2(b + 2) + 20
(-3 * 3 + b * 3) = -2(b + 2) + 20
(-9 + 3b) = -2(b + 2) + 20

Reorder the terms:
-9 + 3b = -2(2 + b) + 20
-9 + 3b = (2 * -2 + b * -2) + 20
-9 + 3b = (-4 + -2b) + 20

Reorder the terms:
-9 + 3b = -4 + 20 + -2b

Combine like terms: -4 + 20 = 16
-9 + 3b = 16 + -2b

Solving
-9 + 3b = 16 + -2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '2b' to each side of the equation.
-9 + 3b + 2b = 16 + -2b + 2b

Combine like terms: 3b + 2b = 5b
-9 + 5b = 16 + -2b + 2b

Combine like terms: -2b + 2b = 0
-9 + 5b = 16 + 0
-9 + 5b = 16

Add '9' to each side of the equation.
-9 + 9 + 5b = 16 + 9

Combine like terms: -9 + 9 = 0
0 + 5b = 16 + 9
5b = 16 + 9

Combine like terms: 16 + 9 = 25
5b = 25

Divide each side by '5'.
b = 5

Simplifying
b = 5

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