3(3z-1)-3(3-4z)=18

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Solution for 3(3z-1)-3(3-4z)=18 equation: 



3(3z-1)-3(3-4z)=18

We move all terms to the left:

3(3z-1)-3(3-4z)-(18)=0

We add all the numbers together, and all the variables

3(3z-1)-3(-4z+3)-18=0

We multiply parentheses

9z+12z-3-9-18=0

We add all the numbers together, and all the variables

21z-30=0

We move all terms containing z to the left, all other terms to the right

21z=30

z=30/21

z=1+3/7

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