3(3z-2)-3(4-2z)=6

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Solution for 3(3z-2)-3(4-2z)=6 equation: 



3(3z-2)-3(4-2z)=6

We move all terms to the left:

3(3z-2)-3(4-2z)-(6)=0

We add all the numbers together, and all the variables

3(3z-2)-3(-2z+4)-6=0

We multiply parentheses

9z+6z-6-12-6=0

We add all the numbers together, and all the variables

15z-24=0

We move all terms containing z to the left, all other terms to the right

15z=24

z=24/15

z=1+3/5

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