3(3z+5)=2(5z-2)

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Solution for 3(3z+5)=2(5z-2) equation: 



3(3z+5)=2(5z-2)

We move all terms to the left:

3(3z+5)-(2(5z-2))=0

We multiply parentheses

9z-(2(5z-2))+15=0



We calculate terms in parentheses: -(2(5z-2)), so:

2(5z-2)

We multiply parentheses

10z-4

Back to the equation:

-(10z-4)



We get rid of parentheses

9z-10z+4+15=0

We add all the numbers together, and all the variables

-1z+19=0

We move all terms containing z to the left, all other terms to the right

-z=-19

z=-19/-1

z=+19

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