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3(3x-5)+x=12(3x+5)+3
We move all terms to the left:
3(3x-5)+x-(12(3x+5)+3)=0
We add all the numbers together, and all the variables
x+3(3x-5)-(12(3x+5)+3)=0
We multiply parentheses
x+9x-(12(3x+5)+3)-15=0
We calculate terms in parentheses: -(12(3x+5)+3), so:We add all the numbers together, and all the variables
12(3x+5)+3
We multiply parentheses
36x+60+3
We add all the numbers together, and all the variables
36x+63
Back to the equation:
-(36x+63)
10x-(36x+63)-15=0
We get rid of parentheses
10x-36x-63-15=0
We add all the numbers together, and all the variables
-26x-78=0
We move all terms containing x to the left, all other terms to the right
-26x=78
x=78/-26
x=-3
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