2x+3(x-4)=2(x+6)+x

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Solution for 2x+3(x-4)=2(x+6)+x equation: 



2x+3(x-4)=2(x+6)+x

We move all terms to the left:

2x+3(x-4)-(2(x+6)+x)=0

We multiply parentheses

2x+3x-(2(x+6)+x)-12=0



We calculate terms in parentheses: -(2(x+6)+x), so:

2(x+6)+x

We add all the numbers together, and all the variables

x+2(x+6)

We multiply parentheses

x+2x+12

We add all the numbers together, and all the variables

3x+12

Back to the equation:

-(3x+12)



We add all the numbers together, and all the variables

5x-(3x+12)-12=0

We get rid of parentheses

5x-3x-12-12=0

We add all the numbers together, and all the variables

2x-24=0

We move all terms containing x to the left, all other terms to the right

2x=24

x=24/2

x=12

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