-(4x-5)-(7x-6)+8=-13(x-1)-(3x+12)+

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Solution for -(4x-5)-(7x-6)+8=-13(x-1)-(3x+12)+ equation: 



-(4x-5)-(7x-6)+8=-13(x-1)-(3x+12)+

We move all terms to the left:

-(4x-5)-(7x-6)+8-(-13(x-1)-(3x+12)+)=0

We get rid of parentheses

-4x-7x-(-13(x-1)-(3x+12)+)+5+6+8=0



We calculate terms in parentheses: -(-13(x-1)-(3x+12)+), so:

-13(x-1)-(3x+12)+

We add all the numbers together, and all the variables

-13(x-1)-(3x+12)

We multiply parentheses

-13x-(3x+12)+13

We get rid of parentheses

-13x-3x-12+13

We add all the numbers together, and all the variables

-16x+1

Back to the equation:

-(-16x+1)



We add all the numbers together, and all the variables

-11x-(-16x+1)+19=0

We get rid of parentheses

-11x+16x-1+19=0

We add all the numbers together, and all the variables

5x+18=0

We move all terms containing x to the left, all other terms to the right

5x=-18

x=-18/5

x=-3+3/5

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