(w-8)(w+5)=14+w2

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Solution for (w-8)(w+5)=14+w2 equation:



(w-8)(w+5)=14+w2
We move all terms to the left:
(w-8)(w+5)-(14+w2)=0
We add all the numbers together, and all the variables
-(+w^2+14)+(w-8)(w+5)=0
We get rid of parentheses
-w^2+(w-8)(w+5)-14=0
We multiply parentheses ..
-w^2+(+w^2+5w-8w-40)-14=0
We add all the numbers together, and all the variables
-1w^2+(+w^2+5w-8w-40)-14=0
We get rid of parentheses
-1w^2+w^2+5w-8w-40-14=0
We add all the numbers together, and all the variables
-3w-54=0
We move all terms containing w to the left, all other terms to the right
-3w=54
w=54/-3
w=-18

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