3(3x-2)=2(6x+5)

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Solution for 3(3x-2)=2(6x+5) equation: 



3(3x-2)=2(6x+5)

We move all terms to the left:

3(3x-2)-(2(6x+5))=0

We multiply parentheses

9x-(2(6x+5))-6=0



We calculate terms in parentheses: -(2(6x+5)), so:

2(6x+5)

We multiply parentheses

12x+10

Back to the equation:

-(12x+10)



We get rid of parentheses

9x-12x-10-6=0

We add all the numbers together, and all the variables

-3x-16=0

We move all terms containing x to the left, all other terms to the right

-3x=16

x=16/-3

x=-5+1/3

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