5(5y-1)-4=3(4y+5)+1

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Solution for 5(5y-1)-4=3(4y+5)+1 equation: 



5(5y-1)-4=3(4y+5)+1

We move all terms to the left:

5(5y-1)-4-(3(4y+5)+1)=0

We multiply parentheses

25y-(3(4y+5)+1)-5-4=0



We calculate terms in parentheses: -(3(4y+5)+1), so:

3(4y+5)+1

We multiply parentheses

12y+15+1

We add all the numbers together, and all the variables

12y+16

Back to the equation:

-(12y+16)



We add all the numbers together, and all the variables

25y-(12y+16)-9=0

We get rid of parentheses

25y-12y-16-9=0

We add all the numbers together, and all the variables

13y-25=0

We move all terms containing y to the left, all other terms to the right

13y=25

y=25/13

y=1+12/13

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