3(3x-2)=-3(x-11)-3

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Solution for 3(3x-2)=-3(x-11)-3 equation: 



3(3x-2)=-3(x-11)-3

We move all terms to the left:

3(3x-2)-(-3(x-11)-3)=0

We multiply parentheses

9x-(-3(x-11)-3)-6=0



We calculate terms in parentheses: -(-3(x-11)-3), so:

-3(x-11)-3

We multiply parentheses

-3x+33-3

We add all the numbers together, and all the variables

-3x+30

Back to the equation:

-(-3x+30)



We get rid of parentheses

9x+3x-30-6=0

We add all the numbers together, and all the variables

12x-36=0

We move all terms containing x to the left, all other terms to the right

12x=36

x=36/12

x=3

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