-5/7x+20=-4/3x

Solution for -5/7x+20=-4/3x equation:

-5/7x+20=-4/3x

We move all terms to the left:

-5/7x+20-(-4/3x)=0


Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R



Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We get rid of parentheses

-5/7x+4/3x+20=0

We calculate fractions


(-15x)/21x^2+28x/21x^2+20=0

We multiply all the terms by the denominator


(-15x)+28x+20*21x^2=0

We add all the numbers together, and all the variables

28x+(-15x)+20*21x^2=0

Wy multiply elements

420x^2+28x+(-15x)=0

We get rid of parentheses

420x^2+28x-15x=0

We add all the numbers together, and all the variables

420x^2+13x=0

a = 420; b = 13; c = 0;
Δ = b2-4ac
Δ = 132-4·420·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-13}{2*420}=\frac{-26}{840}
=-13/420
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+13}{2*420}=\frac{0}{840}
=0
$