3(3x-2)+4x=13(x-2)

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Solution for 3(3x-2)+4x=13(x-2) equation: 



3(3x-2)+4x=13(x-2)

We move all terms to the left:

3(3x-2)+4x-(13(x-2))=0

We add all the numbers together, and all the variables

4x+3(3x-2)-(13(x-2))=0

We multiply parentheses

4x+9x-(13(x-2))-6=0



We calculate terms in parentheses: -(13(x-2)), so:

13(x-2)

We multiply parentheses

13x-26

Back to the equation:

-(13x-26)



We add all the numbers together, and all the variables

13x-(13x-26)-6=0

We get rid of parentheses

13x-13x+26-6=0

We add all the numbers together, and all the variables

20!=0

There is no solution for this equation

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