3(3x+4)-6x=11(x+2)-5

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Solution for 3(3x+4)-6x=11(x+2)-5 equation: 



3(3x+4)-6x=11(x+2)-5

We move all terms to the left:

3(3x+4)-6x-(11(x+2)-5)=0

We add all the numbers together, and all the variables

-6x+3(3x+4)-(11(x+2)-5)=0

We multiply parentheses

-6x+9x-(11(x+2)-5)+12=0



We calculate terms in parentheses: -(11(x+2)-5), so:

11(x+2)-5

We multiply parentheses

11x+22-5

We add all the numbers together, and all the variables

11x+17

Back to the equation:

-(11x+17)



We add all the numbers together, and all the variables

3x-(11x+17)+12=0

We get rid of parentheses

3x-11x-17+12=0

We add all the numbers together, and all the variables

-8x-5=0

We move all terms containing x to the left, all other terms to the right

-8x=5

x=5/-8

x=-5/8

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