16-3x=(2/3)x+5

Solution for 16-3x=(2/3)x+5 equation:

16-3x=(2/3)x+5

We move all terms to the left:

16-3x-((2/3)x+5)=0


Domain of the equation: 3)x+5)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-3x-((+2/3)x+5)+16=0

We multiply all the terms by the denominator


-3x*3)x+5)-((+16*3)x+5)+2=0

We add all the numbers together, and all the variables

-3x*3)x+5)-(48x+5)+2=0

Wy multiply elements

-9x^2=0

a = -9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-9)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-18}=0$