20-10(j+3)=-2(1+4j)-3j

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Solution for 20-10(j+3)=-2(1+4j)-3j equation: 



20-10(j+3)=-2(1+4j)-3j

We move all terms to the left:

20-10(j+3)-(-2(1+4j)-3j)=0

We add all the numbers together, and all the variables

-10(j+3)-(-2(4j+1)-3j)+20=0

We multiply parentheses

-10j-(-2(4j+1)-3j)-30+20=0



We calculate terms in parentheses: -(-2(4j+1)-3j), so:

-2(4j+1)-3j

We add all the numbers together, and all the variables

-3j-2(4j+1)

We multiply parentheses

-3j-8j-2

We add all the numbers together, and all the variables

-11j-2

Back to the equation:

-(-11j-2)



We add all the numbers together, and all the variables

-10j-(-11j-2)-10=0

We get rid of parentheses

-10j+11j+2-10=0

We add all the numbers together, and all the variables

j-8=0

We move all terms containing j to the left, all other terms to the right

j=8

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