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4(3x+3)=6(2+2x)
We move all terms to the left:
4(3x+3)-(6(2+2x))=0
We add all the numbers together, and all the variables
4(3x+3)-(6(2x+2))=0
We multiply parentheses
12x-(6(2x+2))+12=0
We calculate terms in parentheses: -(6(2x+2)), so:We get rid of parentheses
6(2x+2)
We multiply parentheses
12x+12
Back to the equation:
-(12x+12)
12x-12x-12+12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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