3(3x+3)5x+1=26

Solution for 3(3x+3)5x+1=26 equation:

3(3x+3)5x+1=26

We move all terms to the left:

3(3x+3)5x+1-(26)=0

We add all the numbers together, and all the variables

3(3x+3)5x-25=0

We multiply parentheses

45x^2+45x-25=0

a = 45; b = 45; c = -25;
Δ = b2-4ac
Δ = 452-4·45·(-25)
Δ = 6525
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6525}=\sqrt{225*29}=\sqrt{225}*\sqrt{29}=15\sqrt{29}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-15\sqrt{29}}{2*45}=\frac{-45-15\sqrt{29}}{90}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+15\sqrt{29}}{2*45}=\frac{-45+15\sqrt{29}}{90}
$