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3(3x+10)-(x+1)=6(x+10)
We move all terms to the left:
3(3x+10)-(x+1)-(6(x+10))=0
We multiply parentheses
9x-(x+1)-(6(x+10))+30=0
We get rid of parentheses
9x-x-(6(x+10))-1+30=0
We calculate terms in parentheses: -(6(x+10)), so:We add all the numbers together, and all the variables
6(x+10)
We multiply parentheses
6x+60
Back to the equation:
-(6x+60)
8x-(6x+60)+29=0
We get rid of parentheses
8x-6x-60+29=0
We add all the numbers together, and all the variables
2x-31=0
We move all terms containing x to the left, all other terms to the right
2x=31
x=31/2
x=15+1/2
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