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4(2x+1)=2(x+1)+6(x+2)
We move all terms to the left:
4(2x+1)-(2(x+1)+6(x+2))=0
We multiply parentheses
8x-(2(x+1)+6(x+2))+4=0
We calculate terms in parentheses: -(2(x+1)+6(x+2)), so:We get rid of parentheses
2(x+1)+6(x+2)
We multiply parentheses
2x+6x+2+12
We add all the numbers together, and all the variables
8x+14
Back to the equation:
-(8x+14)
8x-8x-14+4=0
We add all the numbers together, and all the variables
-10!=0
There is no solution for this equation
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