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3(3x+1)=8-5(3x-3)
We move all terms to the left:
3(3x+1)-(8-5(3x-3))=0
We multiply parentheses
9x-(8-5(3x-3))+3=0
We calculate terms in parentheses: -(8-5(3x-3)), so:We get rid of parentheses
8-5(3x-3)
determiningTheFunctionDomain -5(3x-3)+8
We multiply parentheses
-15x+15+8
We add all the numbers together, and all the variables
-15x+23
Back to the equation:
-(-15x+23)
9x+15x-23+3=0
We add all the numbers together, and all the variables
24x-20=0
We move all terms containing x to the left, all other terms to the right
24x=20
x=20/24
x=5/6
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