8(4-4n)=128

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Solution for 8(4-4n)=128 equation: 



8(4-4n)=128

We move all terms to the left:

8(4-4n)-(128)=0

We add all the numbers together, and all the variables

8(-4n+4)-128=0

We multiply parentheses

-32n+32-128=0

We add all the numbers together, and all the variables

-32n-96=0

We move all terms containing n to the left, all other terms to the right

-32n=96

n=96/-32

n=-3

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