3(3x+1)=7(2x+5)

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Solution for 3(3x+1)=7(2x+5) equation: 



3(3x+1)=7(2x+5)

We move all terms to the left:

3(3x+1)-(7(2x+5))=0

We multiply parentheses

9x-(7(2x+5))+3=0



We calculate terms in parentheses: -(7(2x+5)), so:

7(2x+5)

We multiply parentheses

14x+35

Back to the equation:

-(14x+35)



We get rid of parentheses

9x-14x-35+3=0

We add all the numbers together, and all the variables

-5x-32=0

We move all terms containing x to the left, all other terms to the right

-5x=32

x=32/-5

x=-6+2/5

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