20(4/5x-1)=20(3/4x+7)

Solution for 20(4/5x-1)=20(3/4x+7) equation:

20(4/5x-1)=20(3/4x+7)

We move all terms to the left:

20(4/5x-1)-(20(3/4x+7))=0


Domain of the equation: 5x-1)!=0

x∈R



Domain of the equation: 4x+7))!=0

x∈R


We multiply parentheses

80x-(20(3/4x+7))-20=0

We multiply all the terms by the denominator


80x*4x-20*4x+7))-(20(3+7))=0

We add all the numbers together, and all the variables

80x*4x-20*4x+7))-(2010)=0

We add all the numbers together, and all the variables

80x*4x-20*4x=0

Wy multiply elements

320x^2-80x=0

a = 320; b = -80; c = 0;
Δ = b2-4ac
Δ = -802-4·320·0
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-80}{2*320}=\frac{0}{640}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+80}{2*320}=\frac{160}{640}
=1/4
$