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3(3x+1)=4(1-3x)
We move all terms to the left:
3(3x+1)-(4(1-3x))=0
We add all the numbers together, and all the variables
3(3x+1)-(4(-3x+1))=0
We multiply parentheses
9x-(4(-3x+1))+3=0
We calculate terms in parentheses: -(4(-3x+1)), so:We get rid of parentheses
4(-3x+1)
We multiply parentheses
-12x+4
Back to the equation:
-(-12x+4)
9x+12x-4+3=0
We add all the numbers together, and all the variables
21x-1=0
We move all terms containing x to the left, all other terms to the right
21x=1
x=1/21
x=1/21
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