3(3x+1)-2(x-5)=x+27

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Solution for 3(3x+1)-2(x-5)=x+27 equation: 



3(3x+1)-2(x-5)=x+27

We move all terms to the left:

3(3x+1)-2(x-5)-(x+27)=0

We multiply parentheses

9x-2x-(x+27)+3+10=0

We get rid of parentheses

9x-2x-x-27+3+10=0

We add all the numbers together, and all the variables

6x-14=0

We move all terms containing x to the left, all other terms to the right

6x=14

x=14/6

x=2+1/3

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