2x(x-8x)=+3x

Solution for 2x(x-8x)=+3x equation:

2x(x-8x)=+3x

We move all terms to the left:

2x(x-8x)-(+3x)=0

We add all the numbers together, and all the variables

2x(-7x)-(+3x)=0

We multiply parentheses

-14x^2-(+3x)=0

We get rid of parentheses

-14x^2-3x=0

a = -14; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·(-14)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*-14}=\frac{0}{-28}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*-14}=\frac{6}{-28}
=-3/14
$