3(3k+2)=13k-18

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Solution for 3(3k+2)=13k-18 equation: 



3(3k+2)=13k-18

We move all terms to the left:

3(3k+2)-(13k-18)=0

We multiply parentheses

9k-(13k-18)+6=0

We get rid of parentheses

9k-13k+18+6=0

We add all the numbers together, and all the variables

-4k+24=0

We move all terms containing k to the left, all other terms to the right

-4k=-24

k=-24/-4

k=+6

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