2(k+2)+7k+2=3(3k+2)

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Solution for 2(k+2)+7k+2=3(3k+2) equation: 



2(k+2)+7k+2=3(3k+2)

We move all terms to the left:

2(k+2)+7k+2-(3(3k+2))=0

We add all the numbers together, and all the variables

7k+2(k+2)-(3(3k+2))+2=0

We multiply parentheses

7k+2k-(3(3k+2))+4+2=0



We calculate terms in parentheses: -(3(3k+2)), so:

3(3k+2)

We multiply parentheses

9k+6

Back to the equation:

-(9k+6)



We add all the numbers together, and all the variables

9k-(9k+6)+6=0

We get rid of parentheses

9k-9k-6+6=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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