3(3d-4)+12=10d-5

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Solution for 3(3d-4)+12=10d-5 equation: 



3(3d-4)+12=10d-5

We move all terms to the left:

3(3d-4)+12-(10d-5)=0

We multiply parentheses

9d-(10d-5)-12+12=0

We get rid of parentheses

9d-10d+5-12+12=0

We add all the numbers together, and all the variables

-1d+5=0

We move all terms containing d to the left, all other terms to the right

-d=-5

d=-5/-1

d=+5

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