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-3(v+5)=3v-3+2(6v+2)
We move all terms to the left:
-3(v+5)-(3v-3+2(6v+2))=0
We multiply parentheses
-3v-(3v-3+2(6v+2))-15=0
We calculate terms in parentheses: -(3v-3+2(6v+2)), so:We get rid of parentheses
3v-3+2(6v+2)
determiningTheFunctionDomain 3v+2(6v+2)-3
We multiply parentheses
3v+12v+4-3
We add all the numbers together, and all the variables
15v+1
Back to the equation:
-(15v+1)
-3v-15v-1-15=0
We add all the numbers together, and all the variables
-18v-16=0
We move all terms containing v to the left, all other terms to the right
-18v=16
v=16/-18
v=-8/9
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