3(3d-1)=4(d+3)

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Solution for 3(3d-1)=4(d+3) equation: 



3(3d-1)=4(d+3)

We move all terms to the left:

3(3d-1)-(4(d+3))=0

We multiply parentheses

9d-(4(d+3))-3=0



We calculate terms in parentheses: -(4(d+3)), so:

4(d+3)

We multiply parentheses

4d+12

Back to the equation:

-(4d+12)



We get rid of parentheses

9d-4d-12-3=0

We add all the numbers together, and all the variables

5d-15=0

We move all terms containing d to the left, all other terms to the right

5d=15

d=15/5

d=3

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