3(3c+17)+3=-20c-4

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Solution for 3(3c+17)+3=-20c-4 equation: 



3(3c+17)+3=-20c-4

We move all terms to the left:

3(3c+17)+3-(-20c-4)=0

We multiply parentheses

9c-(-20c-4)+51+3=0

We get rid of parentheses

9c+20c+4+51+3=0

We add all the numbers together, and all the variables

29c+58=0

We move all terms containing c to the left, all other terms to the right

29c=-58

c=-58/29

c=-2

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