2(n-4)=3n+12

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Solution for 2(n-4)=3n+12 equation: 



2(n-4)=3n+12

We move all terms to the left:

2(n-4)-(3n+12)=0

We multiply parentheses

2n-(3n+12)-8=0

We get rid of parentheses

2n-3n-12-8=0

We add all the numbers together, and all the variables

-1n-20=0

We move all terms containing n to the left, all other terms to the right

-n=20

n=20/-1

n=-20

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