3(3a-2)=8-12a+4(2a+3)

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Solution for 3(3a-2)=8-12a+4(2a+3) equation: 



3(3a-2)=8-12a+4(2a+3)

We move all terms to the left:

3(3a-2)-(8-12a+4(2a+3))=0

We multiply parentheses

9a-(8-12a+4(2a+3))-6=0



We calculate terms in parentheses: -(8-12a+4(2a+3)), so:

8-12a+4(2a+3)

determiningTheFunctionDomain
-12a+4(2a+3)+8

We multiply parentheses

-12a+8a+12+8

We add all the numbers together, and all the variables

-4a+20

Back to the equation:

-(-4a+20)



We get rid of parentheses

9a+4a-20-6=0

We add all the numbers together, and all the variables

13a-26=0

We move all terms containing a to the left, all other terms to the right

13a=26

a=26/13

a=2

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