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(2x+3)(3x+2)=(x-5)(6x-1)
We move all terms to the left:
(2x+3)(3x+2)-((x-5)(6x-1))=0
We multiply parentheses ..
(+6x^2+4x+9x+6)-((x-5)(6x-1))=0
We calculate terms in parentheses: -((x-5)(6x-1)), so:We get rid of parentheses
(x-5)(6x-1)
We multiply parentheses ..
(+6x^2-1x-30x+5)
We get rid of parentheses
6x^2-1x-30x+5
We add all the numbers together, and all the variables
6x^2-31x+5
Back to the equation:
-(6x^2-31x+5)
6x^2-6x^2+4x+9x+31x+6-5=0
We add all the numbers together, and all the variables
44x+1=0
We move all terms containing x to the left, all other terms to the right
44x=-1
x=-1/44
x=-1/44
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