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3(3a-10)=2(2a+15)
We move all terms to the left:
3(3a-10)-(2(2a+15))=0
We multiply parentheses
9a-(2(2a+15))-30=0
We calculate terms in parentheses: -(2(2a+15)), so:We get rid of parentheses
2(2a+15)
We multiply parentheses
4a+30
Back to the equation:
-(4a+30)
9a-4a-30-30=0
We add all the numbers together, and all the variables
5a-60=0
We move all terms containing a to the left, all other terms to the right
5a=60
a=60/5
a=12
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