F(x)=1/2(x+2)(x-4)

Solution for F(x)=1/2(x+2)(x-4) equation:

(F)=1/2(F+2)(F-4)

We move all terms to the left:

(F)-(1/2(F+2)(F-4))=0


Domain of the equation: 2(F+2)(F-4))!=0

F∈R


We multiply parentheses ..

-(1/2(+F^2-4F+2F-8))+F=0

We multiply all the terms by the denominator


-(1+F*2(+F^2-4F+2F-8))=0


We calculate terms in parentheses: -(1+F*2(+F^2-4F+2F-8)), so:

1+F*2(+F^2-4F+2F-8)

determiningTheFunctionDomain
F*2(+F^2-4F+2F-8)+1

Wy multiply elements

2F^2(++1

We use the square of the difference formula

2F^2(+1

Back to the equation:

-(2F^2(+1)


We add all the numbers together, and all the variables

-(2F^21=0

We do not support eFpression: F^21