3(37-5)=(4x+20)

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Solution for 3(37-5)=(4x+20) equation: 



3(37-5)=(4x+20)

We move all terms to the left:

3(37-5)-((4x+20))=0

We add all the numbers together, and all the variables

-((4x+20))+332=0



We calculate terms in parentheses: -((4x+20)), so:

(4x+20)

We get rid of parentheses

4x+20

Back to the equation:

-(4x+20)



We get rid of parentheses

-4x-20+332=0

We add all the numbers together, and all the variables

-4x+312=0

We move all terms containing x to the left, all other terms to the right

-4x=-312

x=-312/-4

x=+78

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