1(x+52)=-20(5-x)

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Solution for 1(x+52)=-20(5-x) equation: 



1(x+52)=-20(5-x)

We move all terms to the left:

1(x+52)-(-20(5-x))=0

We add all the numbers together, and all the variables

1(x+52)-(-20(-1x+5))=0



We calculate terms in parentheses: -(-20(-1x+5)), so:

-20(-1x+5)

We multiply parentheses

20x-100

Back to the equation:

-(20x-100)



We get rid of parentheses

1(x+52)-20x+100=0

We add all the numbers together, and all the variables

-20x+1(x+52)+100=0

We move all terms containing x to the left, all other terms to the right

-20x+1(x+52)=-100

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