3(30+y)=4(y+19)

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Solution for 3(30+y)=4(y+19) equation: 



3(30+y)=4(y+19)

We move all terms to the left:

3(30+y)-(4(y+19))=0

We add all the numbers together, and all the variables

3(y+30)-(4(y+19))=0

We multiply parentheses

3y-(4(y+19))+90=0



We calculate terms in parentheses: -(4(y+19)), so:

4(y+19)

We multiply parentheses

4y+76

Back to the equation:

-(4y+76)



We get rid of parentheses

3y-4y-76+90=0

We add all the numbers together, and all the variables

-1y+14=0

We move all terms containing y to the left, all other terms to the right

-y=-14

y=-14/-1

y=+14

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