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2(x-1+6x)=4(2x-1)+2
We move all terms to the left:
2(x-1+6x)-(4(2x-1)+2)=0
We add all the numbers together, and all the variables
2(7x-1)-(4(2x-1)+2)=0
We multiply parentheses
14x-(4(2x-1)+2)-2=0
We calculate terms in parentheses: -(4(2x-1)+2), so:We get rid of parentheses
4(2x-1)+2
We multiply parentheses
8x-4+2
We add all the numbers together, and all the variables
8x-2
Back to the equation:
-(8x-2)
14x-8x+2-2=0
We add all the numbers together, and all the variables
6x=0
x=0/6
x=0
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