3(3/2-3x)=-18

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Solution for 3(3/2-3x)=-18 equation: 



3(3/2-3x)=-18

We move all terms to the left:

3(3/2-3x)-(-18)=0



Domain of the equation: 2-3x)!=0

We move all terms containing x to the left, all other terms to the right

-3x)!=-2

x!=-2/1

x!=-2

x∈R



We add all the numbers together, and all the variables

3(-3x+3/2)-(-18)=0

We add all the numbers together, and all the variables

3(-3x+3/2)+18=0

We multiply parentheses

-9x+18+3/2*3=0

We multiply all the terms by the denominator


-9x*2*3+3+18*2*3=0

We add all the numbers together, and all the variables

-9x*2*3+111=0

Wy multiply elements

-54x*3+111=0

Wy multiply elements

-162x+111=0

We move all terms containing x to the left, all other terms to the right

-162x=-111

x=-111/-162

x=37/54

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