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2x+15=4x-5/3(x)
We move all terms to the left:
2x+15-(4x-5/3(x))=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2x-(+4x-5/3x)+15=0
We get rid of parentheses
2x-4x+5/3x+15=0
We multiply all the terms by the denominator
2x*3x-4x*3x+15*3x+5=0
Wy multiply elements
6x^2-12x^2+45x+5=0
We add all the numbers together, and all the variables
-6x^2+45x+5=0
a = -6; b = 45; c = +5;
Δ = b2-4ac
Δ = 452-4·(-6)·5
Δ = 2145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-\sqrt{2145}}{2*-6}=\frac{-45-\sqrt{2145}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+\sqrt{2145}}{2*-6}=\frac{-45+\sqrt{2145}}{-12} $
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