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3(3-x)=2(2+x)
We move all terms to the left:
3(3-x)-(2(2+x))=0
We add all the numbers together, and all the variables
3(-1x+3)-(2(x+2))=0
We multiply parentheses
-3x-(2(x+2))+9=0
We calculate terms in parentheses: -(2(x+2)), so:We get rid of parentheses
2(x+2)
We multiply parentheses
2x+4
Back to the equation:
-(2x+4)
-3x-2x-4+9=0
We add all the numbers together, and all the variables
-5x+5=0
We move all terms containing x to the left, all other terms to the right
-5x=-5
x=-5/-5
x=1
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