6(6-x)=2(3+2x)

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Solution for 6(6-x)=2(3+2x) equation: 



6(6-x)=2(3+2x)

We move all terms to the left:

6(6-x)-(2(3+2x))=0

We add all the numbers together, and all the variables

6(-1x+6)-(2(2x+3))=0

We multiply parentheses

-6x-(2(2x+3))+36=0



We calculate terms in parentheses: -(2(2x+3)), so:

2(2x+3)

We multiply parentheses

4x+6

Back to the equation:

-(4x+6)



We get rid of parentheses

-6x-4x-6+36=0

We add all the numbers together, and all the variables

-10x+30=0

We move all terms containing x to the left, all other terms to the right

-10x=-30

x=-30/-10

x=+3

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