3(3-a)-17=17a-4(2+5a)

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Solution for 3(3-a)-17=17a-4(2+5a) equation: 



3(3-a)-17=17a-4(2+5a)

We move all terms to the left:

3(3-a)-17-(17a-4(2+5a))=0

We add all the numbers together, and all the variables

3(-1a+3)-(17a-4(5a+2))-17=0

We multiply parentheses

-3a-(17a-4(5a+2))+9-17=0



We calculate terms in parentheses: -(17a-4(5a+2)), so:

17a-4(5a+2)

We multiply parentheses

17a-20a-8

We add all the numbers together, and all the variables

-3a-8

Back to the equation:

-(-3a-8)



We add all the numbers together, and all the variables

-3a-(-3a-8)-8=0

We get rid of parentheses

-3a+3a+8-8=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0

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