3(3-2x)-2(x-2)=18

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Solution for 3(3-2x)-2(x-2)=18 equation: 



3(3-2x)-2(x-2)=18

We move all terms to the left:

3(3-2x)-2(x-2)-(18)=0

We add all the numbers together, and all the variables

3(-2x+3)-2(x-2)-18=0

We multiply parentheses

-6x-2x+9+4-18=0

We add all the numbers together, and all the variables

-8x-5=0

We move all terms containing x to the left, all other terms to the right

-8x=5

x=5/-8

x=-5/8

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